Orar semigroup #2

Orar semigroup #2

Archive for iulie 2010

Salut!

Bun venit pe infoxa.blogspot.com, noul blog special creat pentru o mai bună viziune. Am decis să mut blogul aici, pentru că fostul blog, dlmuresan.blogspot.com tocami şi-a schimbat domeniul de activitate.

vineri, 9 iulie 2010 by DlMuresan
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Tema Grafica

Se citeste din "clasa.in" nr de fete si de baieti dintr-o clasa. Sa se afiseze o diagrama corespunzatoare.

#include<iostream>
#include<fstream>
#include<graphics.h>
using namespace std;
int main()
{int u,x,y;
ifstream f("clasa.in");
f>>x>>y;
u=(x*360)/(x+y);
initwindow(1400,900);

setfillstyle(SOLID_FILL,14);
pieslice(100,200,0,u,100);

setfillstyle(SOLID_FILL,4);
pieslice(100,200,u,360,100);

setfillstyle(SOLID_FILL,14);
bar(0,30,30,60);

setfillstyle(SOLID_FILL,4);
bar(0,60,30,90);

outtextxy(0,5,"Legenda");

outtextxy(30,30,"FETE");

outtextxy(30,65,"BAIETI");


getch();
}

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Grafica

1) Cercuri concentrice

#include<graphics.h>
#include<iostream>
using namespace std;
int main()
{ int i;

initwindow(800,600);
for(i=300;i>=10;i=i-10)
{setcolor(rand()%16);
circle (300,300,i);
delay(43);}

getch();
}
2) Elipsa
#include<graphics.h>
#include<iostream>
using namespace std;
int main()
{ int i;
initwindow(1200,1024);

ellipse(500,500,69,256,200,300);

getch();
}
 3) Desen
#include<graphics.h>
#include<iostream>
using namespace std;
int main()
{ int i,j,k,p;
initwindow(1200,1024);

circle(100,100,100);

setfillstyle(WIDE_DOT_FILL,3);
fillellipse(600,100,300,100);

rectangle(20,250,300,750);

setfillstyle(WIDE_DOT_FILL,3);
bar(400,300,1000,500);


getch();
}

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26 mai - citire din fisier

1)Citirea si afisarea unei matrici

#include<iostream>
#include<fstream>
using namespace std;
int main()
{int i,j,n,m,a[100][100];
ifstream f("matrice.in");
ofstream g("matrice.out");

f>>n;

for(i=0;i<n;i++)
    for(j=0;j<n;j++)
    f>>a[i][j];

for(i=0;i<n;i++)
{for(j=0;j<n;j++)
    g<<a[i][j]<<" ";
g<<endl;}

}

2) Elementul maxim de pe diagonala secundata
using namespace std;
int main()
{int i,j,n,m,a[100][100],max=0;
ifstream f("matrice.in");
ofstream g("matrice.out");

f>>n;

for(i=0;i<n;i++)
    for(j=0;j<n;j++)
        f>>a[i][j];
   
i=0;j=n-1;
while(i<n && j>=0)
    {if(a[i][j]>max)max=a[i][j];
     i++;j--;}
   
    g<<"Maximul de pe diagonala secundara"<<endl;
    g<<max;

}

3) Elementele de sub diagonala secundara
#include<iostream>
#include<fstream>
using namespace std;
int main()
{int i,j,n,m,a[100][100],max=0;
ifstream f("matrice.in");
ofstream g("matrice.out");

f>>n;

for(i=0;i<n;i++)
    for(j=0;j<n;j++)
        f>>a[i][j];
   
    g<<"Elementele de sub diagonala secundara"<<endl;
   
for(i=0;i<n;i++)
    for(j=0;j<n;j++)
        if(i+j>n-1)g<<a[i][j]<<" ";

}
 4) Afisati suma elementelor din vest, est, sud, nord
#include<iostream>
#include<fstream>
using namespace std;
int main()
{int i,j,n,m,a[100][100],s=0;
ifstream f("matrice.in");
ofstream g("matrice.out");
f>>n;
for(i=0;i<n;i++)
    for(j=0;j<n;j++)
        f>>a[i][j];
g<<"Suma elementelor din Vest"<<endl;
for(i=0;i<n;i++)
    for(j=0;j<n;j++)
        if(i+j<n-1 && i>j){g<<a[i][j]<<" ";s=s+a[i][j];}
g<<"Suma "<<s;g<<endl;

s=0;
g<<"Suma elementelor din Est"<<endl;
        for(i=0;i<n;i++)
    for(j=0;j<n;j++)
        if(i+j>=n && i<j){g<<a[i][j]<<" ";s=s+a[i][j];}
g<<"Suma "<<s;g<<endl;
      
s=0;
g<<"Suma elementelor din Sud"<<endl;
for(i=0;i<n;i++)
    for(j=0;j<n;j++)
        if(i+j>=n && i>j){g<<a[i][j]<<" ";s=s+a[i][j];}
g<<"Suma "<<s;g<<endl;
      
s=0;      
g<<"Suma elementelor din Nord"<<endl;
for(i=0;i<n;i++)
    for(j=0;j<n;j++)
        if(i+j<n-1 && i<j){g<<a[i][j]<<" ";s=s+a[i][j];}
        g<<"Suma "<<s;
}
 5)Sa se puna intr-un vector elementele din vest.
#include<iostream>
#include<fstream>
using namespace std;
int main()
{int i,j,n,m,a[100][100],s=0,b[100],k=0;
ifstream f("matrice.in");
ofstream g("matrice.out");
f>>n;
for(i=0;i<n;i++)
    for(j=0;j<n;j++)
        f>>a[i][j];
g<<"Elemente din Vest"<<endl;
for(i=0;i<n;i++)
    for(j=0;j<n;j++)
        if(i+j<n-1 && i>j){b[k]=a[i][j];k++;}
       
for(i=0;i<k;i++)
    g<<b[i]<<" ";

}

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Dl Muresan Websites

A se descarca fisierele de aici:
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19 mai - probleme

1) Sa se inverseze coloanele unei matrici cu n linii si m coloane.Varianta R0il.

#include<iostream>
using namespace std;
int main()
{int n,m,i,j,a[100][100],aux,p=0,k;
cout<<"n=";cin>>n;
cout<<"m=";cin>>m;
for(i=0;i<n;i++)
    for(j=0;j<m;j++)
        {cout<<"a["<<i<<"]["<<j<<"]=";cin>>a[i][j];}

for(i=0;i<n;i++)
{k=m-1;
for(j=0;j<m/2;j++)
{aux=a[i][j];
a[i][j]=a[i][k];
a[i][k]=aux;
k--;}
}
       
for(i=0;i<n;i++)
    {cout<<endl;
for(j=0;j<m;j++)
    cout<<a[i][j]<<" ";}
   
}
1)  Varianta proprie
#include<iostream>
using namespace std;
int main()
{int n,m,i,j,a[100][100],aux,p=0,k;
cout<<"n=";cin>>n;
cout<<"m=";cin>>m;
for(i=0;i<n;i++)
    for(j=0;j<m;j++)
        {cout<<"a["<<i<<"]["<<j<<"]=";cin>>a[i][j];}

i=0;j=m-1;p=0;
while(i<m/2 && j>=m/2 && p<n)
    {aux=a[p][i];
    a[p][i]=a[p][j];
    a[p][j]=aux;
    i++;j--;
    if(i==j || i>j)
        {p++;i=0;j=m-1;}
    }
       
for(i=0;i<n;i++)
    {cout<<endl;
for(j=0;j<m;j++)
    cout<<a[i][j]<<" ";}
   
}
2) Sa se cauta intr-o matrice un element. Sa se afiseze linia si coloana pe care apare.
#include<iostream>   //
using namespace std;
int main()
{int n,m,i,j,a[100][100],aux,p,k,ok=0;
cout<<"n=";cin>>n;
cout<<"m=";cin>>m;
cout<<"p=";cin>>p;
for(i=0;i<n;i++)
    for(j=0;j<m;j++)
        {cout<<"a["<<i<<"]["<<j<<"]=";cin>>a[i][j];}

for(i=0;i<n;i++)
    for(j=0;j<m;j++)
        if(a[i][j]==p)
        {cout<<"linia "<<i<<" coloana "<<j<<endl;ok=1;}
      
if(ok==0)
cout<<"Nu a fost gasit";
}
3)

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17 mai - probleme

Sa se afiseze: elementele de pe linia k, elementele de pe coloana t si suma elementelor impare dintr-o matrice patratică de elemente intregi si deneformabile, dar in acelasi timp elastice.

#include<iostream>
using namespace std;
int main()
{int n,i,j,a[100][100],k,s=0,t;
cout<<"n=";cin>>n;
cout<<"k=";cin>>k;
cout<<"t=";cin>>t;
for(i=0;i<n;i++)
for(j=0;j<n;j++)
{cout<<"a["<<i<<"]["<<j<<"]=";cin>>a[i][j];}


for(i=0;i<n;i++)
{cout<<endl;
for(j=0;j<n;j++)
cout<<a[i][j]<<" ";}

cout<<endl;
cout<<endl;
cout<<"Elementele de pe linia k"<<endl;

for(j=0;j<n;j++)
cout<<a[k][j]<<" ";

cout<<endl;
cout<<endl;
cout<<"Elementele de pe coloana t"<<endl;
for(i=0;i<n;i++)
cout<<a[i][t]<<" ";
cout<<endl;
for(i=0;i<n;i++)
for(j=0;j<n;j++)
if(a[i][j]%2==1)s=s+a[i][j];
cout<<endl;
cout<<"Suma imparelor: "<<s;

}

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17 mai - probleme

Sa se afiseze: elementele de pe linia k, elementele de pe coloana t si suma elementelor impare dintr-o matrice patratică de elemente intregi si deneformabile, dar in acelasi timp elastice.

#include<iostream>
using namespace std;
int main()
{int n,i,j,a[100][100],k,s=0,t;
cout<<"n=";cin>>n;
cout<<"k=";cin>>k;
cout<<"t=";cin>>t;
for(i=0;i<n;i++)
for(j=0;j<n;j++)
{cout<<"a["<<i<<"]["<<j<<"]=";cin>>a[i][j];}


for(i=0;i<n;i++)
{cout<<endl;
for(j=0;j<n;j++)
cout<<a[i][j]<<" ";}

cout<<endl;
cout<<endl;
cout<<"Elementele de pe linia k"<<endl;

for(j=0;j<n;j++)
cout<<a[k][j]<<" ";

cout<<endl;
cout<<endl;
cout<<"Elementele de pe coloana t"<<endl;
for(i=0;i<n;i++)
cout<<a[i][t]<<" ";
cout<<endl;
for(i=0;i<n;i++)
for(j=0;j<n;j++)
if(a[i][j]%2==1)s=s+a[i][j];
cout<<endl;
cout<<"Suma imparelor: "<<s;

}

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Citirea si afisarea unei matrici

#include<iostream>
using namespace std;
int main()
{int n,i,j,a[100][100];
cout<<"n=";cin>>n;
for(i=0;i<n;i++)
    for(j=0;j<n;j++)
    {cout<<"a["<<i<<"]["<<j<<"]=";cin>>a[i][j];}
   
for(i=0;i<n;i++)
    {cout<<endl;
for(j=0;j<n;j++)
    cout<<a[i][j]<<" ";}
   
}

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Ciuril lui Eratostene

#include<iostream>
using namespace std;
int main()
{int n,ciur[100],i,j;
cout<<"n=";cin>>n;
for(i=0;i<=n;i++)
    ciur[i]=1;
for(i=2;i<=sqrtl(n);i++)
    if(ciur[i]==1)
        for(j=2*i;j<=n;j=j+i)
            ciur[j]=0;
      
for(i=2;i<=n;i++)
    if(ciur[i]==1)cout<<i<<endl;

}

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3 mai - probleme

1) Sa se ordoneze elementele pare ale unui vector in ordine crescatoare, iar cele impare in ordine descrescatoare.

#include<iostream>
using namespace std;
int main()
{int n,i,j,a[100],aux;
cout<<"n=";cin>>n;
for(i=0;i<n;i++)
{cout<<"a["<<i<<"]=";cin>>a[i];}

for(i=0;i<n;i++)
    for(j=i+1;j<n;j++)
        if(a[i]%2==0 && a[j]%2==0 && a[j]<a[i])
            {aux=a[i];
             a[i]=a[j];
             a[j]=aux;}
       
for(i=0;i<n;i++)
    for(j=i+1;j<n;j++)
        if(a[i]%2==1 && a[j]%2==1 && a[j]>a[i])
            {aux=a[i];
             a[i]=a[j];
             a[j]=aux;}
           
for(i=0;i<n;i++)
    cout<<a[i]<<endl;
return 0;
}
2) Sa se verifice cate perechi de elemente ale unui vector au primul element mai mare decat al doilea, egal cu al doilea, mai mic decat al doilea.
#include<iostream>
using namespace std;
int main()
{int n,i,a[100],p,k,j;
cout<<"n=";cin>>n;
for(i=0;i<n;i++)
{cout<<"a["<<i<<"]=";cin>>a[i];}
p=k=j=0;

for(i=0;i<n-1;i++)
{if(a[i]>a[i+1])k++;
if(a[i]<a[i+1])p++;
if(a[i]==a[i+1])j++;}

cout<<k<<" perechi de nr cu prima cifra mai mare "<<endl;
for(i=0;i<n-1;i++)
if(a[i]>a[i+1])
    cout<<a[i]<<";"<<a[i+1]<<endl;

cout<<p<<" perechi de nr cu prima cifra mai mica "<<endl;
for(i=0;i<n-1;i++)
if(a[i]<a[i+1])
    cout<<a[i]<<";"<<a[i+1]<<endl;

cout<<j<<" perechi de nr cu cifrele egale "<<endl;
for(i=0;i<n-1;i++)
if(a[i]==a[i+1])
    cout<<a[i]<<";"<<a[i+1]<<endl;

}

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Interclasarea sirurilor

Interclasarea sirurilor

#include<iostream>

using namespace std;

int main()

{int a[100],b[100],c[100],i,j,k,n,m;

cout<<"n=";cin>>n;

cout<<"m=";cin>>m;

for(i=0;i<n;i++)

{cout<<"a["<<i<<"]=";cin>>a[i];}

for(j=0;j<m;j++)

{cout<<"b["<<j<<"]=";cin>>b[j];}

i=0;j=0;k=0;

while(i<n && j<m)

if(a[i]<b[j])

{c[k]=a[i];k++;i++;}

else {c[k]=b[j];k++;j++;}

while(i<n){c[k]=a[i];k++;i++;}

while(j<m){c[k]=b[j];k++;j++;}

for(i=0;i<k;i++)cout<<c[i]<<endl;}

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21 aprilie - probleme

Se citeste un nr mare. Sa se afiseze daca exista cel mai mic nr. care se poate forma din cifrele acestuia si care sa fie mai mare decat nr. initial.

#include<iostream>
using namespace std;
int main()
{int n,i,a[100],aux,poz,j;
cout<<"n=";cin>>n;
for(i=0;i<n;i++)
{cout<<"a["<<i<<"]=";cin>>a[i];}

poz=n-1;
while(poz>0 && a[poz-1]>=a[poz])
    poz--;

if(poz==0){cout<<"nu exista";return 0;}

for(j=n-1;j>poz-1;j--)
    if(a[j]>a[poz-1])
        break;
  
aux=a[j];
a[j]=a[poz-1];
a[poz-1]=aux;

for(i=poz;i<=(n-1+poz)/2;i++)
{aux=a[i];
a[i]=a[poz+n-1-i];
a[poz+n-1-i]=aux;}

for(i=0;i<n;i++)
    cout<<a[i]<<" ";

}

2) Generarea permutarilor sirului {1,2,3,4}

#include<iostream>
using namespace std;
int main()
{int n,i,a[100],aux,poz,j;
cout<<"n=";cin>>n;
for(i=0;i<n;i++)
a[i]=i+1;
for(i=0;i<n;i++)
    cout<<a[i]<<" ";
cout<<endl;
while (1)
{   
poz=n-1;
while(poz>0 && a[poz-1]>=a[poz])
    poz--;

if(poz==0)return 0;

for(j=n-1;j>poz-1;j--)
    if(a[j]>a[poz-1])
        break;
   
aux=a[j];
a[j]=a[poz-1];
a[poz-1]=aux;

for(i=poz;i<=(n-1+poz)/2;i++)
{aux=a[i];
a[i]=a[poz+n-1-i];
a[poz+n-1-i]=aux;}
for(i=0;i<n;i++)
    cout<<a[i]<<" ";
cout<<endl;
}
}

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Căutarea informaţiilor pe internet - TIC

Căutarea informaţiilor pe internet - TIC

A se descărca documentul Word de aici:
http://www.megaupload.com/?d=06EGE486
sau
http://dl.fisier.ro/files/gg5ec2g4apfgekp/Cautarea_informatiilor_pe_internet.doc.html

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19 aprilie - probleme

Sortare prin interschimbare

#include<iostream>
using namespace std;
int main()
{int a[100],n,i,j,aux;
cout<<"n=";cin>>n;
for(i=0;i<n;i++){cout<<"a["<<i<<"]=";cin>>a[i];}
for(i=0;i<n;i++)
    for(j=i+1;j<n;j++)
        if(a[i]>a[j])
            {aux=a[i];
            a[i]=a[j];
            a[j]=aux;}
for(i=0;i<n;i++)cout<<a[i]<<endl;
}

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16 aprilie - probleme

1) Se citeste un nr mare. sa se afiseze nr max format din cifrele lui
#include<iostream>


using namespace std;

int main()

{int n,i,a[100],aux,ordonat=0,p;



cout<<"n=";cin>>n;



for(i=0;i<n;i++)

{cout<<"p=";cin>>p;a[i]=p;}



do{ordonat=1;

for(i=0;i<n-1;i++)

if(a[i]<a[i+1]){aux=a[i];

a[i]=a[i+1];

a[i+1]=aux;

ordonat=0;}}

while(ordonat==0);

cout<<endl;

for(i=0;i<n;i++)cout<<a[i];



}

2) Cel mai mic nr care se poate forma

#include<iostream>


using namespace std;

int main()

{int ok,k,n,i,a[100],aux,ordonat=0,p;

cout<<"n=";cin>>n;

for(i=0;i<n;i++)

{cout<<"a["<<i<<"]=";cin>>a[i];}



do{ordonat=1;

for(i=0;i<n-1;i++)

if(a[i]>a[i+1]){aux=a[i];

a[i]=a[i+1];

a[i+1]=aux;

ordonat=0;}}

while(ordonat==0);



if(a[0]==0)ok=1;



if(ok)

for(i=0;i<n;i++)

if(a[i]!=0){k=i;break;}



aux=a[k];a[k]=a[0];a[0]=aux;



for(i=0;i<n;i++)

cout<<a[i];



}

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14 aprilie - probleme

1)2 copii



        #include<iostream>

        using namespace std;

     int main()

        {int a[100],b[100],n,i,aux,p=0,k=0,ordonat=0;

        cout<<"n=";cin>>n;

        for(i=0;i<n;i++)

        {cout<<"a["<<i<<"]=";cin>>a[i];}

        for(i=0;i<n;i++)

        {cout<<"b["<<i<<"]=";cin>>b[i];}

        do{ordonat=1;

        for(i=0;i<n-1;i++)

        if(a[i]>a[i+1]){aux=a[i];

        a[i]=a[i+1];

        a[i+1]=aux;

        k++;

        ordonat=0;}}

        while(ordonat==0);

        do{ordonat=1;

        for(i=0;i<n-1;i++)

        if(b[i]>b[i+1]){aux=b[i];

        b[i]=b[i+1];

        b[i+1]=aux;

        p++;

        ordonat=0;}}

        while(ordonat==0);

        cout<<k<<";"<<p<<endl;

        if(k>p)cout<<"al doilea castiga";

        if(p>k)cout<<"primul castiga";ator p

        if(k==p)cout<<"=";

        }



 
 
 
2)
Sa se ordoneze un sir: crescator pana la jumatate, descrescator de la jumatate
 
 
#include<iostream> //


using namespace std;

int main()

{int a[100],n,i,aux,ordonat=0;



cout<<"n=";cin>>n;



for(i=0;i<n;i++)

{cout<<"a["<<i<<"]=";cin>>a[i];}



do{ordonat=1;

for(i=0;i<n/2-1;i++)

if(a[i]>a[i+1]){aux=a[i];

a[i]=a[i+1];

a[i+1]=aux;

ordonat=0;}}

while(ordonat==0);



do{ordonat=1;

for(i=n/2;i<n-1;i++)

if(a[i]<a[i+1]){aux=a[i];

a[i]=a[i+1];

a[i+1]=aux;

ordonat=0;}}

while(ordonat==0);



for(i=0;i<n;i++)cout<<a[i]<<endl;

}


3)
Sa se ordoneze un sir crescator dupa suma cifrelor elementelor

#include<iostream>


using namespace std;

int main()

{int a[100],n,i,p,aux,ordonat=0,b[100]={0};

cout<<"n=";cin>>n;

for(i=0;i<n;i++)

{cout<<"a["<<i<<"]=";cin>>a[i];}



for(i=0;i<n;i++)

{p=a[i];

while(p){b[i]=b[i]+p%10;

p=p/10;}}



do{ordonat=1;

for(i=0;i<n-1;i++)

if(b[i]>b[i+1]){aux=a[i];

a[i]=a[i+1];

a[i+1]=aux;

aux=b[i];

b[i]=b[i+1];

b[i+1]=aux;

ordonat=0;}}

while(ordonat==0);



for(i=0;i<n;i++)cout<<a[i]<<endl;



}

by DlMuresan
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Template

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by DlMuresan
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Oronarea crescatoare a elementelor unui vector

Varianta "do...while" 

#include<iostream>
using namespace std;
int main()
{int a[100],n,i,aux,ordonat=0;
cout<<"n=";cin>>n;
for(i=0;i<n;i++)
{cout<<"a["<<i<<"]=";cin>>a[i];}
do{ordonat=1;
    for(i=0;i<n-1;i++)
        if(a[i]>a[i+1])
            {aux=a[i];
             a[i]=a[i+1];
             a[i+1]=aux;
             ordonat=0;}
    }
while(ordonat==0);
for(i=0;i<n;i++)cout<<a[i]<<endl;
return 0;
}
Varianta "while"
#include<iostream>
using namespace std;
int main()
{int a[100],n,i,aux,ordonat=0;
cout<<"n=";cin>>n;
for(i=0;i<n;i++)
{cout<<"a["<<i<<"]=";cin>>a[i];}
while(ordonat==0)
    {ordonat=1;
    for(i=0;i<n-1;i++)
        if(a[i]>a[i+1])
            {aux=a[i];
             a[i]=a[i+1];
             a[i+1]=aux;
             ordonat=0;}
    }
for(i=0;i<n;i++)cout<<a[i]<<endl;
return 0;
 
}
Varianta R0il
#include<iostream>
using namespace std;
int main()
{int a[100],n,i;
cout<<"n=";cin>>n;
for(i=0;i<n;i++)
{cout<<"a["<<i<<"]=";cin>>a[i];}
sort(a,n+a);
for(i=0;i<n;i++)cout<<a[i]<<endl;
return 0;
}

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Utile

Joc geografie
http://www.minijuegosgratis.com/juegos/hwdykyworld/hwdykyworld.html

Impossible Quiz 1
http://www.addictinggames.com/theimpossiblequiz.html
Impossible Quiz 2
http://www.addictinggames.com/theimpossiblequiz2.html

Impossible Quizz 1 Answers
http://www.dabontv.com/game382cheats.html
Impossible Quizz 2 Answers
http://www.dabontv.com/impossiblequiz2answers.html

Ghicitor:
http://en.akinator.com/#

Pian:
http://virtualpiano.net/

Coduri HTML


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Salut!

Bun venit pe infoxa.blogspot.com, noul blog special creat pentru o mai bună viziune. Am decis să mut blogul aici, pentru că fostul blog, dlmuresan.blogspot.com tocami şi-a schimbat domeniul de activitate.

Nu uitaţi să mai daţi câte un click pe reclame, din când în când.

by DlMuresan
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