Orar semigroup #2

Orar semigroup #2

14 aprilie - probleme

1)2 copii



        #include<iostream>

        using namespace std;

     int main()

        {int a[100],b[100],n,i,aux,p=0,k=0,ordonat=0;

        cout<<"n=";cin>>n;

        for(i=0;i<n;i++)

        {cout<<"a["<<i<<"]=";cin>>a[i];}

        for(i=0;i<n;i++)

        {cout<<"b["<<i<<"]=";cin>>b[i];}

        do{ordonat=1;

        for(i=0;i<n-1;i++)

        if(a[i]>a[i+1]){aux=a[i];

        a[i]=a[i+1];

        a[i+1]=aux;

        k++;

        ordonat=0;}}

        while(ordonat==0);

        do{ordonat=1;

        for(i=0;i<n-1;i++)

        if(b[i]>b[i+1]){aux=b[i];

        b[i]=b[i+1];

        b[i+1]=aux;

        p++;

        ordonat=0;}}

        while(ordonat==0);

        cout<<k<<";"<<p<<endl;

        if(k>p)cout<<"al doilea castiga";

        if(p>k)cout<<"primul castiga";ator p

        if(k==p)cout<<"=";

        }



 
 
 
2)
Sa se ordoneze un sir: crescator pana la jumatate, descrescator de la jumatate
 
 
#include<iostream> //


using namespace std;

int main()

{int a[100],n,i,aux,ordonat=0;



cout<<"n=";cin>>n;



for(i=0;i<n;i++)

{cout<<"a["<<i<<"]=";cin>>a[i];}



do{ordonat=1;

for(i=0;i<n/2-1;i++)

if(a[i]>a[i+1]){aux=a[i];

a[i]=a[i+1];

a[i+1]=aux;

ordonat=0;}}

while(ordonat==0);



do{ordonat=1;

for(i=n/2;i<n-1;i++)

if(a[i]<a[i+1]){aux=a[i];

a[i]=a[i+1];

a[i+1]=aux;

ordonat=0;}}

while(ordonat==0);



for(i=0;i<n;i++)cout<<a[i]<<endl;

}


3)
Sa se ordoneze un sir crescator dupa suma cifrelor elementelor

#include<iostream>


using namespace std;

int main()

{int a[100],n,i,p,aux,ordonat=0,b[100]={0};

cout<<"n=";cin>>n;

for(i=0;i<n;i++)

{cout<<"a["<<i<<"]=";cin>>a[i];}



for(i=0;i<n;i++)

{p=a[i];

while(p){b[i]=b[i]+p%10;

p=p/10;}}



do{ordonat=1;

for(i=0;i<n-1;i++)

if(b[i]>b[i+1]){aux=a[i];

a[i]=a[i+1];

a[i+1]=aux;

aux=b[i];

b[i]=b[i+1];

b[i+1]=aux;

ordonat=0;}}

while(ordonat==0);



for(i=0;i<n;i++)cout<<a[i]<<endl;



}

vineri, 9 iulie 2010 by DlMuresan
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